Solution:
VAW = VAS + VSW
where VAS = 5.0 m/s with the course 300 North of East
VWS = 1.5 m/s in the direction of South
thus,
VSW = 1.5 m/s in the direction of North
We can now draw the vector diagram the represents the vector equation.
We can now solve for VAW.
b) The distance upstream is easily solved by determining the time of crossing using VASx and
then calculating vertical displacement using VASy.
c) The vector equation for the velocity of the boat with respect to the
shore is given by,
VBS = VBW + VWS
where VBW = 2.5 m/s with a heading of 550 South of East
VWS = 1.5 m/s in the direction of South
The vector diagram should be drawn to aid in seeing the following calculations.
d) The time to cross the river is then simply calculated using the width of the river and the
x-component of VBS.
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