Assorted Circuits 2
Solutions:
1. 
B  
2. 
A  
3. 
C  
4. 
D  
5. 


6. 
a)


b) 


c)  The "new" resistance of the circuit would be
32.0 W and therefore the current in the
circuit 1.875A. This means the voltage drop across the 12.0 W
resistor has increased from 4.0 V to 7.5 V, thus the 12.0 W
bulb now burns brighter.


7. 
If the voltage drop across the unknown resistor is 3.0
V, then the voltage drop across the 15 kW
resistor and the 17 kW resistor in series
must be 6.0 V, thus the current in the circuit is
So the value of the unknown resistor is given by

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